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Math Help - algebra...please help

  1. #1
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    Exclamation algebra...please help

    Solve for x.

    x/5 - x + 2/3 = 1/5

    I need someones to please explain how to get the answer to this problem. Thanx so much!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by cutiepi_86 View Post
    Solve for x.

    x/5 - x + 2/3 = 1/5

    I need someones to please explain how to get the answer to this problem. Thanx so much!
    x/5 - x + 2/3 = 1/5 .............let's begin by trying to get all the x's on one side
    => x/5 - x = 1/5 - 2/3 .........subtracted 2/3 from both sides
    => (x - 5x)/5 = -7/15 ..........combined fractions on both sides
    => x - 5x = -7/3 .................multiplied through by 5
    => -4x = -7/3 ....................added all the x's to get them in one term
    => x = 7/12 .......................divided both sides by -4
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  3. #3
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    Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

    Sorry...I wrote it out wrong the first time.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by cutiepi_86 View Post
    Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

    Sorry...I wrote it out wrong the first time.
    no, it's not the same problem. for this one:

    x/5 - (x + 2)/3 = 1/5 ...............first let's combine the fractions on the left
    => (3x - 5(x + 2))/15 = 1/5
    => 3x - 5(x + 2) = 3 ...............multiplied both sides by 15
    => 3x - 5x - 10 = 3 ................expanded the brackets
    => -2x - 10 = 3 .....................combined the x's
    => -2x = 13 ..........................added 10 to both sides
    => x = -13/2 .........................divided both sides by -2


    parenthesis are important
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by cutiepi_86 View Post
    Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

    Sorry...I wrote it out wrong the first time.
    No it isn't the same.

    x/5 - (x + 2)/3 = 1/5

    Let's get rid of those pesky fractions. The LCM of 3 and 5 is 15, so I'm going to multiply both sides of the equation by 15:
    15(x/5 - (x + 2)/3) = 15(1/5)

    3x - 5(x + 2) = 3

    3x - 5x - 10 = 3

    -2x = 13

    x = 13/(-2) = -13/2

    -Dan
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  6. #6
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    Thanks SO much Jhevon & Dan! Your the best!
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