Solve for x.

x/5 - x + 2/3 = 1/5

I need someones to please explain how to get the answer to this problem. Thanx so much!

2. Originally Posted by cutiepi_86
Solve for x.

x/5 - x + 2/3 = 1/5

I need someones to please explain how to get the answer to this problem. Thanx so much!
x/5 - x + 2/3 = 1/5 .............let's begin by trying to get all the x's on one side
=> x/5 - x = 1/5 - 2/3 .........subtracted 2/3 from both sides
=> (x - 5x)/5 = -7/15 ..........combined fractions on both sides
=> x - 5x = -7/3 .................multiplied through by 5
=> -4x = -7/3 ....................added all the x's to get them in one term
=> x = 7/12 .......................divided both sides by -4

3. Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

Sorry...I wrote it out wrong the first time.

4. Originally Posted by cutiepi_86
Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

Sorry...I wrote it out wrong the first time.
no, it's not the same problem. for this one:

x/5 - (x + 2)/3 = 1/5 ...............first let's combine the fractions on the left
=> (3x - 5(x + 2))/15 = 1/5
=> 3x - 5(x + 2) = 3 ...............multiplied both sides by 15
=> 3x - 5x - 10 = 3 ................expanded the brackets
=> -2x - 10 = 3 .....................combined the x's
=> -2x = 13 ..........................added 10 to both sides
=> x = -13/2 .........................divided both sides by -2

parenthesis are important

5. Originally Posted by cutiepi_86
Would it be the same if the problem was written out x/5 - (x + 2)/3 = 1/5 ??

Sorry...I wrote it out wrong the first time.
No it isn't the same.

x/5 - (x + 2)/3 = 1/5

Let's get rid of those pesky fractions. The LCM of 3 and 5 is 15, so I'm going to multiply both sides of the equation by 15:
15(x/5 - (x + 2)/3) = 15(1/5)

3x - 5(x + 2) = 3

3x - 5x - 10 = 3

-2x = 13

x = 13/(-2) = -13/2

-Dan

6. Thanks SO much Jhevon & Dan! Your the best!