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Math Help - Rational Inequality Problem

  1. #1
    Junior Member
    Joined
    Apr 2010
    Posts
    43

    Rational Inequality Problem

    <br />
\frac{8x+9}{x+3} > \frac{x+3}{x-1}<br />

    I forgot how to solve these, don't you multiply each side by each's side denominator?

    <br />
\frac{(8x+9)(x-1)}{x+3} - \frac{(x+3)(x+3)}{x-1} > 0<br />

    <br />
\frac{(8x^2+x-9)-(x^2+6x+9)}{(x+3)(x-1)}<br />

    <br />
\frac{7x^2-5x-18}{(x+3)(x-1)}<br />


    Thanks!
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  2. #2
    Super Member
    Joined
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    Thanks
    4
    7x^2 - 5x - 18 >0

    Factorize this, you will get,
    (7x+9)(x-2)>0
    Now find the range of the x values which satisfies the above condition.
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