Transpose the formula $\displaystyle {v} = \sqrt{x+2y}$ for y I got $\displaystyle \frac{v^2-x}{2} = y $
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Originally Posted by jimgreenmore Transpose the formula $\displaystyle {v} = \sqrt{x+2y}$ for y I got $\displaystyle \frac{v^2-x}{2} = y $ That's correct
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