Results 1 to 4 of 4

Math Help - Hyperbola general form

  1. #1
    Member
    Joined
    Jan 2010
    Posts
    142

    Hyperbola general form

    i have given equations:

     x^2-y=3 <== parabola I already got this one.
     4x^2-y^2+2y=5 ==> how to form into general form  \frac {(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}?

    This i have this far:

    4x^2-(y^2+2y+1)=5+4-1

     4(x-0)^2 - (y+2)^2 = 8

     \frac {(x-0)^2}{2}-\frac{(y+2)^2}{8}=1

     a=\sqrt(2), b=\sqrt(8), and (h,k) = (0,-2)

    Am I wrong or right? thanks in advance////
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Jun 2009
    Posts
    806
    Thanks
    4

    4x^2 - y^2 + 2y - 1 = 5 - 1
    4x^2 - ( y - 1)^2 = 4
    {x^2 - \frac{(y-1)^2}{2^2}}= 1
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Jan 2010
    Posts
    142
    Quote Originally Posted by sa-ri-ga-ma View Post

    4x^2 - y^2 + 2y - 1 = 5 - 1
    4x^2 - ( y - 1)^2 = 4
    {x^2 - \frac{(y-1)^2}{2^2}}= 1

    Ah i see...

    so a=1, b=2 and (h,k) = (0,1) right?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member
    Joined
    Jun 2009
    Posts
    806
    Thanks
    4
    Quote Originally Posted by Anemori View Post
    Ah i see...

    so a=1, b=2 and (h,k) = (0,1) right?
    Yes. You are right.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Put Equation in Standard Hyperbola form
    Posted in the Algebra Forum
    Replies: 2
    Last Post: July 23rd 2011, 11:32 PM
  2. Replies: 1
    Last Post: May 11th 2010, 11:39 AM
  3. Replies: 2
    Last Post: March 9th 2010, 08:33 PM
  4. Replies: 1
    Last Post: February 16th 2010, 07:21 AM
  5. rewrite in slope-intercepr form and general form
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: August 10th 2005, 08:50 PM

Search Tags


/mathhelpforum @mathhelpforum