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Math Help - Re-arrange-ment

  1. #1
    Junior Member
    Joined
    Nov 2009
    Posts
    58

    Re-arrange-ment

    Hi,

    Could anyone run me through getting from this:

    2\sqrt(6) + 5 = p/q

    to this:

    \sqrt(6) = (p - 5q)/(10q)

    I can't see how it could be done!

    Thanks
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  2. #2
    Super Member Anonymous1's Avatar
    Joined
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    Big Red, NY
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    Thanks
    1
    Quote Originally Posted by aceband View Post
    Hi,

    Could anyone run me through getting from this:

    2\sqrt(6) + 5 = p/q

    to this:

    \sqrt(6) = (p - 5q)/(10q)

    I can't see how it could be done!

    Thanks
    2\sqrt{6} + 5 = \frac{p}{q}

    \implies 2\sqrt{6} = \frac{p}{q} - 5

    \implies \sqrt{6} = \frac{1}{2}\cdot\frac{p}{q} - \frac{5}{2}

    \implies \sqrt{6} = \frac{p}{2q} - \frac{5q}{2q}

    \implies \sqrt{6} = \frac{p-5q}{2q}
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