Certain Question

**KatanaMaster95** · May 6th 2010, 10:15 AM

I made it into a Picture file, please help:

**Anonymous1** · May 6th 2010, 11:08 AM

Originally Posted by KatanaMaster95

I made it into a Picture file, please help:

Plug and chug, as they say...

$(a)$ $S = \frac{n(n+1)}{2}$

$S(1) = \frac{1\cdot(1+1)}{2} = 1.$

$S(2) = \frac{2\cdot(2+1)}{2} = 1 + 2 = 3.$

You try some.

$(b)$ $C = \frac{n^2 (n+1)^2}{4}$

$C(1) = \frac{1^2 \cdot(1+1)^2}{4} = 1^3 = 1.$

$C(2) = \frac{2^2\cdot(2+1)^2}{4} = 1^3 + 2^3 = 9.$

$(c)$ Clearly,

$S^2 = (\frac{n(n+1)}{2})^2 = \frac{n^2(n+1)^2}{2^2} = C.$

So, $S^2 = C.$

**CaptainBlack** · May 6th 2010, 10:50 PM

Originally Posted by Anonymous1

Complete detailed solution to routine question deleted

Do you get extra credit for this from the OP's school?

CB

**Anonymous1** · May 6th 2010, 11:10 PM

I'm sorry, did I do something wrong here? I may have passed over this one in the MHF list of rules.

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