Is it possible to re-arrange 2-1/(n-1)+1/n(n-1) to get 2-1/n? Thanks
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Originally Posted by jpquinn91 Is it possible to re-arrange 2-1/(n-1)+1/n(n-1) to get 2-1/n? Thanks Are you sure you wrote this correctly? $\displaystyle (2-1) = 1$ so$\displaystyle ...$ $\displaystyle \frac{1}{n-1}+\frac{1}{n(n-1)} = \frac{n}{n(n-1)}+\frac{1}{n(n-1)} = \frac{n+1}{n(n-1)}$
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