Factor by grouping
xy + 12 + 4x + 3y = (x+3)(4+y)<-------txtbk ans
x² + x - xy - y = (x+1)(x-y)<--------txtbk ans
Please help. I'm confused how to arrive to the answer. Can someone show me the steps? Thank you!
Only so you can take out a common factor.
Yep, addition commutes.
You try to find groups where there is a common factor that once taken out gives the same inside each bracket. Sometimes might take a little trial and error. Perseverance will be your friend.