Factor by grouping

xy + 12 + 4x + 3y = (x+3)(4+y)<-------txtbk ans

x² + x - xy - y = (x+1)(x-y)<--------txtbk ans

Please help. I'm confused how to arrive to the answer. Can someone show me the steps? Thank you!

Printable View

- May 4th 2010, 10:21 PMlarry21Common Factors
Factor by grouping

xy + 12 + 4x + 3y = (x+3)(4+y)<-------txtbk ans

x² + x - xy - y = (x+1)(x-y)<--------txtbk ans

Please help. I'm confused how to arrive to the answer. Can someone show me the steps? Thank you! - May 4th 2010, 10:23 PMpickslides

Do you follow? - May 4th 2010, 10:33 PMlarry21
- May 5th 2010, 04:45 AMpickslides
Only so you can take out a common factor.

Yep, addition commutes.

You try to find groups where there is a common factor that once taken out gives the same inside each bracket. Sometimes might take a little trial and error. Perseverance will be your friend.