I need help with finding the a and q values if the defining equation f is f(x)= ax^2 + q
with the x and y values being (-3;6) and (3;6)
x y x y
How would u go about solving this equation
Hi Mixxie,
if a=1, then q=-3
You need 2 clues to find "a" and "q".
The two pieces of information you are given are unfortunately
not giving two simultaneous equations as they are both
$\displaystyle 9a+q=6$
since $\displaystyle (-3)^2=3^2$
The graph of the function is parabolic, the axis of symmetry is the y-axis.
$\displaystyle f(0)=q$
There are an infinite number of solutions until another clue is given.
$\displaystyle a=2,\ 2(9)+q=6,\ q=-12$
$\displaystyle a=3,\ 3(9)+q=6,\ q=-21$
etc