I need help with finding the a and q values if the defining equation f is f(x)= ax^2 + q
with the x and y values being (-3;6) and (3;6)
x y x y
How would u go about solving this equation
if a=1, then q=-3
You need 2 clues to find "a" and "q".
The two pieces of information you are given are unfortunately
not giving two simultaneous equations as they are both
The graph of the function is parabolic, the axis of symmetry is the y-axis.
There are an infinite number of solutions until another clue is given.