-4^2+52*5+5^3-(4^2-48/4)

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- May 3rd 2010, 09:05 AMchikaMath problem
-4^2+52*5+5^3-(4^2-48/4)

- May 3rd 2010, 11:27 AMshenanigans87
The problem here is remembering the order of operations.

P E M D A S

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

$\displaystyle -4^2+52\cdot 5+5^3-(4^2-\frac{48}{4})$

Do everything in that order.

$\displaystyle 16+260+125-(16-\frac{48}{4})$

$\displaystyle 401-(4)=397$ - May 3rd 2010, 11:48 AMmasters
Hi chika,

I get something different.

Shenanigans87, your error is in the first term: $\displaystyle \boxed{{\color{red}-4^2=-16}}$

$\displaystyle -4^2+52\cdot 5 +5^3-\left(4^2-\frac{48}{4}\right)$

$\displaystyle -4^2+52\cdot 5 +5^3-16+12$

$\displaystyle -16+260+125-16+12$

Evaluate left to right....$\displaystyle \boxed{365}$ - May 3rd 2010, 11:51 AMshenanigans87
- May 3rd 2010, 07:32 PMmasters