# Math problem

• May 3rd 2010, 09:05 AM
chika
Math problem
-4^2+52*5+5^3-(4^2-48/4)
• May 3rd 2010, 11:27 AM
shenanigans87
Quote:

Originally Posted by chika
-4^2+52*5+5^3-(4^2-48/4)

The problem here is remembering the order of operations.

P E M D A S

Parenthesis
Exponent
Multiply
Divide
Subtract

$\displaystyle -4^2+52\cdot 5+5^3-(4^2-\frac{48}{4})$

Do everything in that order.

$\displaystyle 16+260+125-(16-\frac{48}{4})$

$\displaystyle 401-(4)=397$
• May 3rd 2010, 11:48 AM
masters
Quote:

Originally Posted by chika
-4^2+52*5+5^3-(4^2-48/4)

Hi chika,

I get something different.

Shenanigans87, your error is in the first term: $\displaystyle \boxed{{\color{red}-4^2=-16}}$

$\displaystyle -4^2+52\cdot 5 +5^3-\left(4^2-\frac{48}{4}\right)$

$\displaystyle -4^2+52\cdot 5 +5^3-16+12$

$\displaystyle -16+260+125-16+12$

Evaluate left to right....$\displaystyle \boxed{365}$
• May 3rd 2010, 11:51 AM
shenanigans87
Quote:

Originally Posted by masters
Hi chika,

I get something different.

Shenanigans87, your error is in the first term: $\displaystyle \boxed{{\color{red}-4^2=-16}}$

um... all signs indicate that the problem suggests the first term is $\displaystyle (-4)^2$ which is $\displaystyle (-4)(-4)=16$

I think you are mistaken.
• May 3rd 2010, 07:32 PM
masters
Quote:

Originally Posted by shenanigans87
um... all signs indicate that the problem suggests the first term is $\displaystyle (-4)^2$ which is $\displaystyle (-4)(-4)=16$

I think you are mistaken.

Uh....I don't think so. I see no parenthenses in the original problem.