Hi:

If I have an equation of the sort

$\displaystyle

\ln \left( {3y - 1} \right) = \frac{x}{2}

$

and I want to solve for y, I can anti-log which gives:

$\displaystyle

3y - 1 = e^{\frac{x}{2}}

$

The problem is, I can't understand how the x/2 has now become a power. Because if I multiply ln by e to give lne=1, and I do the same for the RHS which gives ex/2, not $\displaystyle

e^{\frac{x}{2}}

$

can someone help me to understand this please

thank you