Hi everybody, this may be really simple and im just missing the point. But how can you calculate the 2 intersection points of 2 quadratics if one is x^2 and the other is -x^2?
Many thanks
Daniel
$\displaystyle f(x) $ is just another name for y
let $\displaystyle y = y $
=> $\displaystyle x^{2} - 6x + 9 = -x^{2} +7x - 11 $
=> $\displaystyle 2x^{2} - 13x + 20 = 0 $
solve that quadratic for x and find the corresponding y value by subbing x into original equation of curve