Without a calculator evaluate: Log(base 16)1/8 .... I just used the change of base forumla to get Log1/8 over Log16 is this all that can be done? Thanks for help
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Originally Posted by vagina69 Without a calculator evaluate: Log(base 16)1/8 .... I just used the change of base forumla to get Log1/8 over Log16 is this all that can be done? Thanks for help One of the principles of logs is . Since the for any , you can simplify to . There are probably a few ways of going on, but the easiest to me is splitting 8 into . The and so we are left with . As 2 is the fourth root of 16, , and so the . We can now solve
Last edited by ChristopherDunn; May 2nd 2010 at 06:40 PM.
Originally Posted by ChristopherDunn One of the principles of logs is . Since the for any , you can simplify to . There are probably a few ways of going on, but the easiest to me is splitting 8 into . The and so we are left with . As 2 is the fourth root of 16, , and so the . We can now solve Hi Cris, Answer could be clearer and more direct. log base 16 (1/8 ) =logbase 16 ( 2/16)= log base 16 (2) -logbase16 (16) = 1/4 - 1 bjh
Originally Posted by bjhopper Hi Cris, Answer could be clearer and more direct. log base 16 (1/8 ) =logbase 16 ( 2/16)= log base 16 (2) -logbase16 (16) = 1/4 - 1 bjh Ah. Right you are. I did add an extra step in there.
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