Use the quadratic formula to find the zeros of the function
f(x)=x^2-6x+18
i get
x=6 +- Square r0ot of -6^2-4(1)(18)
x=6 +- squareroot of 36-72
which = -36
then
6 +_ 6i
__________
2(1)
=
3+- 3i
right...
Now iT states to put it in factored form
f(x)= a(x-r1)(x-r2)
where a= ?
r1= ?
r2=?
i tried putting a=3
r1=3i
r2=3i
but i guess im wr0ng help please...
=[
thank you so much to everyone on the forum!