Use the quadratic formula to find the zeros of the function

f(x)=x^2-6x+18

i get

x=6 +- Square r0ot of -6^2-4(1)(18)

x=6 +- squareroot of 36-72

which = -36

then

6 +_ 6i

__________

2(1)

=

3+- 3i

right...

Now iT states to put it in factored form

f(x)= a(x-r1)(x-r2)

where a= ?

r1= ?

r2=?

i tried putting a=3

r1=3i

r2=3i

but i guess im wr0ng help please...

=[

thank you so much to everyone on the forum!