The problem asks you to evaluate: Log(base 3)72 WITHOUT A CALCULATOR.
You are given the value of Log(base 3)6 and of Log(base 3)4
How do I solve!!!
Since $\displaystyle \log (xy) = \log (x) + \log (y)$ in any base, find $\displaystyle \log_{3} (3 \times 4 \times 6)$. You should know that $\displaystyle \log_{3} (3) = 1$, so add 1 to the other two logs you were already given.
Last edited by ChristopherDunn; May 2nd 2010 at 04:52 PM.