Hi, i would like to ask you for some help about how to add these exponential logs...
If A = 200e^-0.2m
and B = 10.5e^0.3m
what is A + B
seriously, i cant add them... and what i mean is adding the 2 equations... and by the way i dont know how you guys can make the powers shown here so i just typed '^'... sorry...
I did err in the simplification operations.Here is my revised solution.
A=200 e^-.2m
ln A = ln 200 e^-.2m
ln A =ln 200 -.2m ln e
ln A =5.3 -.2m
e^5.3-.2m =A
B=10.5e^.3m
Ln B = ln 10.5 e^.3m
ln B = ln 10.5 + .3m ln e
lnB =2.35+.3m
e^2.35+.3m =B
A+B= e^5.3-.2m + e^2.35 +.3m
bjh
ln A =ln 200-.2m ln e
ln A =5.3-.2m
e^5.3-.2m =A
[quote=bjhopper;504191]I did err in the simplification operations.Here is my revised solution.
A=200 e^-.2m
ln A = ln 200 e^-.2m
ln A =ln 200 -.2m ln e
ln A =5.3 -.2m
e^5.3-.2m =A
This must be
B=10.5e^.3m
Ln B = ln 10.5 e^.3m
ln B = ln 10.5 + .3m ln e
lnB =2.35+.3m
e^2.35+.3m =B
This must be
A+B= e^5.3-.2m + e^2.35 +.3m
It must be , which is close to what I wrote in my first post (I just didn't do approximations)
Tonio
bjh