how do you get
(2n-1)! / (2n+1)! to equal to
(2n-1)! / (2n+1)(2n)(2n-1)!
well i thought it had something to do with calculus...its the first time I've seen the ! sign people used in a problem
the question was:
determine whether the sequence converges or diverges. If it converges, find the limit.
i just needed to know how that step was done...
we're talking about a SEQUENCE and not a SERIES right. and i suppose you want the limit as n-->oo
well in that case:
yes, the sequence does converge--to zero
lim{n-->oo}[(2n-1)!/(2n+1)! ] = lim{n-->oo}[(2n-1)!/(2n+1)(2n)(2n - 1)!]
.........................................= lim{n-->oo}[1/(2n + 1)(2n)]
.........................................= 0