How do you factor (a+b)^2-(2a-b)^2 and (a+b)^2-4(b+c)^2 without simplifying the expression?
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Originally Posted by sinjid9 How do you factor (a+b)^2-(2a-b)^2 and (a+b)^2-4(b+c)^2 without simplifying the expression? Each of them is a difference of two squares. Remember that . . .
Originally Posted by sinjid9 How do you factor (a+b)^2-(2a-b)^2 and (a+b)^2-4(b+c)^2 without simplifying the expression? (a+b)^2-(2a-b)^2 is in the form of where x = a+b and y = (2a-b) you should know that
Thanks for the help, both of you.
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