Prove Mathematically That...

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April 28th 2010, 05:25 PM
BrendanLoftus

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Prove Mathematically That...

No calculators please....I need to solve by showing each step and what the step is basically doing; I can get all the way up to where I have to deal with the radical in the radical, any help is greatly appreciated.

here is the way it was written; this is a site, i typed it on wolframalpha to get correct symbols: http://www4c.wolframalpha.com/Calcul...=14&w=368&h=47

or attached image below...
April 28th 2010, 05:37 PM
maddas

Square both sides to get $36^2 + 3\cdot 18^2 + 2\cdot36\cdot18\cdot \sqrt{3} = 3(4+2\sqrt{3})(3^2 + 3^2\cdot 3 + 2\cdot3\cdot3\cdot \sqrt{3})$ . Now expand the RHS and collect like terms.
April 28th 2010, 06:00 PM
BrendanLoftus

Quote:

Originally Posted by maddas

Square both sides to get $36^2 + 3\cdot 18^2 + 2\cdot36\cdot18\cdot \sqrt{3} = 3(4+2\sqrt{3})(3^2 + 3^2\cdot 3 + 2\cdot3\cdot3\cdot \sqrt{3})$ . Now expand the RHS and collect like terms.

I am sorry but I am confused; can you possibly explain it a different way, maybe step by step. I do not understand how to expand.
April 28th 2010, 06:06 PM
maddas

Do you know how I got that formula?
April 28th 2010, 06:11 PM
BrendanLoftus

yes, you squared everything. but when i simply, i get:

42+ 24sqrt3= 11 + 6sqrt3 which is a false statement....

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