Given that:
$\displaystyle \frac{2x^4-3x^2+x+1}{x^2-1}=ax^2+bx+c+\frac{dx+e}{x^2-1}$
Find the constants $\displaystyle a,b,c,d$ and $\displaystyle e$
Edit: It was easier than I thought! Solved
Given that:
$\displaystyle \frac{2x^4-3x^2+x+1}{x^2-1}=ax^2+bx+c+\frac{dx+e}{x^2-1}$
Find the constants $\displaystyle a,b,c,d$ and $\displaystyle e$
Edit: It was easier than I thought! Solved