Given that:

$\displaystyle \frac{2x^4-3x^2+x+1}{x^2-1}=ax^2+bx+c+\frac{dx+e}{x^2-1}$

Find the constants $\displaystyle a,b,c,d$ and $\displaystyle e$

Edit: It was easier than I thought! Solved

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- Apr 28th 2010, 09:53 AMQuacky[SOLVED] Partial Fractions/algebraic fractions
Given that:

$\displaystyle \frac{2x^4-3x^2+x+1}{x^2-1}=ax^2+bx+c+\frac{dx+e}{x^2-1}$

Find the constants $\displaystyle a,b,c,d$ and $\displaystyle e$

Edit: It was easier than I thought! Solved