the basic function is f(x) = 1/x

the transformed function that I don't know how to graph is: y = f[(-1/3)x + 1]

Printable View

- April 27th 2010, 02:30 PMneedhelpplease1How to graph this...
the basic function is f(x) = 1/x

the transformed function that I don't know how to graph is: y = f[(-1/3)x + 1] - April 27th 2010, 03:10 PMe^(i*pi)
The way you've written it implies which doesn't fit with the basic function.

I will assume you mean . It's best to do these in a series of steps.

For f(-x) reflect f(x) in the y-axis

For f(ax) increase 'steepness' by a. In this case it means it will come down from more sharply. You're not expected to know the exact shape but you should evaluate f(1) to get a set point. In your case the point will be

For f(x)+b you move the graph up the y axis by b. In your case b=1. This will also move any asymptotes.

---------------------------------

In your case you want the graph of 1/x:

- Reflected in the y-axis
- Steepened by a factor of 3 - passing through
- Moved up by 1 unit on the y-axis

See the graph attached for the final answer, I have included 1/x for comparison. - April 27th 2010, 03:26 PMneedhelpplease1Thank you thank you!
Thanks you SO much! That was amazingly helpful!!