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Math Help - Intercepts & standard form

  1. #1
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    Intercepts & standard form

    Express each of the following in standard form

    y= 1/4x - 1/3
    -4(-1/4x + y +1/3)=(0)-4
    -3(1x - 4y -4/3)=(0)-3
    -3x+12y+4=0
    -3x+12y=-4

    The answer is 3x-12y=4

    I don't know what I did wrong, please help.
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  2. #2
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by buck View Post
    Express each of the following in standard form

    y= 1/4x - 1/3
    -4(-1/4x + y +1/3)=(0)-4
    -3(1x - 4y -4/3)=(0)-3
    -3x+12y+4=0
    -3x+12y=-4

    The answer is 3x-12y=4

    I don't know what I did wrong, please help.
    Your ansswer is correct
    You have  -3x+12y=-4

    so,

     -(3x-12y) = -4 \implies 3x-12y=4


    another method:

    y = \frac{x}{4} - \frac{1}{3} = \frac{3x-4}{12}

    \therefore 12y = 3x-4 \implies 3x-12y=4
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