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Math Help - Factoring by group/grouping

  1. #1
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    Factoring by group/grouping

    Hi, I have a funny little question that is:

    jam - pam - jim + pim

    My workings are like this:
    jam - pam - jim + pim
    = (jam - pam) + (jim - pim)
    = am (j - p) + im (j - p)
    = (am + im)(j - p)

    Can anyone tell me if this is correct? Thank you
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  2. #2
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    Hello, yorkey!

    You missed on a minus-sign and . . .


    Factor: . jam - pam - jim + pim


    My workings are like this:

    jam - pam - jim + pim

    . . =\; (jam - pam) \:{\color{red}-}\: (jim - pim)

    . . =\; am (j - p) \:{\color{red}-}\;im (j - p)

    . . =\; (am \:{\color{red}-}\: im)(j - p)

    . . =\;{\color{red}m}(a-i)(j-p)

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  3. #3
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    Thank you for the quick reply! It's amazing how helpful some people, like yourself, are.

    But I don't understand the 1st line: If I want to change the sign inside the bracket from a plus sign to a negative sign, shouldn't I then change the sign outside of the bracket from a negative sign to a plus sign?
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  4. #4
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    Hi,

    I'm sorry to reply again, but the above question is still bothering me.

    If I have this part of a sum:

    - (jim + pim)
    , won't that change to

    + (jim - pim)
    I swap the signs around?
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  5. #5
    Junior Member
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    Yes an example of this is

    -1(2+3)
    You would just factor -1 into the problem changing them both (-2-3)
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