I don't see anyway to factor this out, does this mean that there is no x intercept?
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By graphing it, or otherwise, you can figure out that x=2 is a root. So factor out (x-2) to get . Now can you factor the quadratic?
Originally Posted by dorkymichelle
I don't see anyway to factor this out, does this mean that there is no x intercept? all cubic polynomials have at least one real zero.
using the rational root theorem reveals that x = 2 is a real root of this cubic.
there may be more ... what can you do now to find them if they exist?
yes thanks, I can find the roots with the quadratic formula, I didnt think of factoring out the (x-2)
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