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Math Help - Are these Alegbra Equations Prime?

  1. #1
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    Are these Alegbra Equations Prime?

    1. 242y^4-200x^6
    2. w^2+w-16
    3. x^8-y^8
    4. 4x^2+y^2
    5. 6ax+3bx-2b-4a
    6. 2x^2+8x+8

    Thanks

    And for the equation 30a^2bc+6abc-12

    is the simplest form of that

    6(5a^2bc+abc-2)

    or can it can go simpler?
    Last edited by HAGEMONSTER; April 25th 2010 at 11:09 AM.
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  2. #2
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    You factored out the 6 incorrectly from the last equation. Check your work please.

    Also what do you mean by a prime algebra equation?
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  3. #3
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    Quote Originally Posted by wonderboy1953 View Post
    You factored out the 6 incorrectly from the last equation. Check your work please.

    Also what do you mean by a prime algebra equation?
    what? i factored the 6 out correctly? 6 from 30 is five. the ^2 is exponet of the a



    and like is it possible to factor out the equations or are they prime like you cant factor them out anymore
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  4. #4
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    Quote Originally Posted by HAGEMONSTER View Post
    1. 242y^4-200x^6 will factor
    2. w^2+w-16 prime
    3. x^8-y^8 will factor
    4. 4x^2+y^2 prime
    5. 6ax+3bx-2b-4a will factor
    6. 2x^2+8x+8 will factor

    Thanks

    And for the equation 30a^2bc+6abc-12

    is the simplest form of that

    6(5a^2bc+abc-2)

    or can it can go simpler? it's as simple as I can see
    ...
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  5. #5
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    oh ok thanks, and can you please explain how x^8 -y^8 can be factored?



    also can

    14y^2 +31y-10 be factored?
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  6. #6
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    for this equation

    6ax+3bx-2b-4a

    i got (3x-2)(2a+b)

    is that right?
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  7. #7
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    Quote Originally Posted by HAGEMONSTER View Post
    oh ok thanks, and can you please explain how x^8 -y^8 can be factored?



    also can

    14y^2 +31y-10 be factored?
    x^8-y^8 = (x^4+y^4)(x^4-y^4) = (x^4+y^4)(x^2+y^2)(x^2-y^2) =  (x^4+y^4)(x^2+y^2)(x+y)(x-y)<br />


    as far as the quadratic expression 14y^2  +31y-10 , you can tell if it can be factored if its discriminant is a perfect square number ...

    31^2 - 4(14)(-10) = 1521 =  39^2 , so it will factor.
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  8. #8
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    Quote Originally Posted by HAGEMONSTER View Post
    for this equation

    6ax+3bx-2b-4a

    i got (3x-2)(2a+b)

    is that right?
    multiply it out and see.
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  9. #9
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    Quote Originally Posted by skeeter View Post

    as far as the quadratic expression 14y^2  +31y-10 , you can tell if it can be factored if its discriminant is a perfect square number ...

    31^2 - 4(14)(-10) = 1521 =  39^2 , so it will factor.
    i dont understand that bottom line lol sorry..?

    NEVERMIND BRO THANKS THO I GOT IT !!!
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