$\displaystyle 5(x+1)^4-5$

the way i did it was

$\displaystyle 5(x+1)^4=5$

$\displaystyle (x+1)^4=1$

$\displaystyle x+1 = 1$

$\displaystyle x = 0$

but, i know there is another answer of -2 because if you get $\displaystyle (-1)^4$ it is also 1...

so i think that i'm not doing this the proper way

can anyone show me the proper way to solve this?