Originally Posted by

**deovolante** Hi,

Is it possible to manipulate a quadratic function

Let's call it $\displaystyle ax^2+bx+c$

so that it has a gradient of 35.5 at the point (1,33)

So $\displaystyle a+b+c=33\,\,\,and\,\,\,also\,\,\,2a+b=35.5$

while forcing it to have an x-intercept of 10 and the other x-intercept being anything less then 10

This means $\displaystyle 100a+10b+c=0$ and also that there must exist $\displaystyle \alpha<10\,\,\,s.t.\,\,\,a\alpha^2+b\alpha+c=0$

. I have no idea how to approach this...

Any help will be greatly appreciated.

Thanks,

John