Dear Sir I would appreciate very much if you can help me with the below question. Thanks very much Kingman find n if n ! = 3 to the power of 2007
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Originally Posted by kingman Dear Sir I would appreciate very much if you can help me with the below question. Thanks very much Kingman find n if n ! = 3 to the power of 2007 Did you mean $\displaystyle n!=3^{2007}$ ? Then don't worry: it has no soution since any factorial with $\displaystyle n\geq 2$ must be even... Tonio
3^2007 ends with an odd digit. 5! = 120; if n>4, last digit always 0. Are you sure you got that problem correct?
i can see that there is something wrong with the question and i will check on it. thanks
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