# Thread: [SOLVED] Basic Functions Question

1. ## [SOLVED] Basic Functions Question

I've solved the defined functions to this answer

$\displaystyle x^2-2x+2kx-4k+36=0$

Then I've converted it into the $\displaystyle ax^2+bx+c$ format like this:

For bx: $\displaystyle (-2x+2kx) = -x(2-2k)$

For c: $\displaystyle (-4k+36)$

So now I have a= 1 b= (2-2k) c= (-4k+36)

Am I doing it right? I'm not getting the correct discriminant/roots with the above.

Any help fellas?

Thanks!

2. Originally Posted by unstopabl3
I've solved the defined functions to this answer

$\displaystyle x^2-2x+2kx-4k+36=0$

Then I've converted it into the $\displaystyle ax^2+bx+c$ format like this:

For bx: $\displaystyle (-2x+2kx) = -x(2-2k)$

For c: $\displaystyle (-4k+36)$

So now I have a= 1 b= (2-2k) c= (-4k+36)

Am I doing it right? I'm not getting the correct discriminant/roots with the above.

Any help fellas?

Thanks!
Dear unstopabl3,

If you want to convert your equation into $\displaystyle ax^2+bx+c$ form, b should be, $\displaystyle b=2k-2$ not $\displaystyle b=2-2k$

Did you get the idea?

3. Originally Posted by unstopabl3
I've solved the defined functions to this answer

$\displaystyle x^2-2x+2kx-4k+36=0$

Then I've converted it into the $\displaystyle ax^2+bx+c$ format like this:

For bx: $\displaystyle (-2x+2kx) = -x(2-2k)$

For c: $\displaystyle (-4k+36)$

So now I have a= 1 b= (2-2k) c= (-4k+36)

Am I doing it right? I'm not getting the correct discriminant/roots with the above.

Any help fellas?

Thanks!
well according to $\displaystyle ax^{2}+bx+c$ your $\displaystyle a=1$ is correct. However your $\displaystyle b$ should be $\displaystyle b = -2 + 2k$ and your $\displaystyle c = -4k + 36$ is also correct.

4. Thanks for the quick replies, got the correct answer now