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Math Help - [SOLVED] Basic Functions Question

  1. #1
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    Cool [SOLVED] Basic Functions Question

    I've solved the defined functions to this answer

    x^2-2x+2kx-4k+36=0

    Then I've converted it into the ax^2+bx+c format like this:

    For bx: (-2x+2kx) = -x(2-2k)

    For c: (-4k+36)

    So now I have a= 1 b= (2-2k) c= (-4k+36)

    Am I doing it right? I'm not getting the correct discriminant/roots with the above.

    Any help fellas?

    Thanks!
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  2. #2
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    Quote Originally Posted by unstopabl3 View Post
    I've solved the defined functions to this answer

    x^2-2x+2kx-4k+36=0

    Then I've converted it into the ax^2+bx+c format like this:

    For bx: (-2x+2kx) = -x(2-2k)

    For c: (-4k+36)

    So now I have a= 1 b= (2-2k) c= (-4k+36)

    Am I doing it right? I'm not getting the correct discriminant/roots with the above.

    Any help fellas?

    Thanks!
    Dear unstopabl3,

    If you want to convert your equation into ax^2+bx+c form, b should be, b=2k-2 not b=2-2k

    Did you get the idea?
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  3. #3
    Junior Member piglet's Avatar
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    Quote Originally Posted by unstopabl3 View Post
    I've solved the defined functions to this answer

    x^2-2x+2kx-4k+36=0

    Then I've converted it into the ax^2+bx+c format like this:

    For bx: (-2x+2kx) = -x(2-2k)

    For c: (-4k+36)

    So now I have a= 1 b= (2-2k) c= (-4k+36)

    Am I doing it right? I'm not getting the correct discriminant/roots with the above.

    Any help fellas?

    Thanks!
    well according to  ax^{2}+bx+c your  a=1 is correct. However your  b should be  b = -2 + 2k and your  c = -4k + 36 is also correct.

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  4. #4
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    Thanks for the quick replies, got the correct answer now
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