Form a polynomial whose zeros are: 1, 2, -2 and has a degree of 3.

Anyone know how to do this ?

Thanks

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- Dec 5th 2005, 05:44 PMjwaingoldPolynomial Zeros
Form a polynomial whose zeros are: 1, 2, -2 and has a degree of 3.

Anyone know how to do this ?

Thanks - Dec 5th 2005, 05:47 PMJamesonQuote:

Originally Posted by**jwaingold**

- Dec 5th 2005, 05:50 PMjwaingold
but what does the degree of 3 part mean ?

- Dec 5th 2005, 05:58 PMMathGurudegree three polynomial
degree of three means that the polynomial will look like this

a*x^3 + b*x^2 + c*x + d

the highest power of x is the degree.

to get your answer you will do something like this:

(x-a)*(x-b)*(x-c) when you multiply it all out you will get the degree three polynomial you are looking for. - Dec 6th 2005, 08:08 AMMathGurufurther explanation
Jwain pm'd me and still doesn't see the answer so I will explain it further.

polynomial is degree three and zeros are: 1, 2, -2

meaning that when x = 1, 2, or -2, y=0

the answer will start from the form of

y=(x-a)*(x-b)*(x-c) where y = zero when x = a, b, or c

does that make sense? let us substitute x=a

y=(a-a)*(a-b)*(a-c)

y=(0)*(a-b)*(a-c)

y=0

now we know the zeros are 1, 2, and -2 so the solution will look like this:

y=(x-1)*(x-2)*(x-(-2))

now simply multiply out the three terms and you will get your polynomial.