Find that value of each variable.
I don't know what the heck I am doing.
Can someone please help?
Also, what is wrong with this problem?
3(x-5)=28
3(x-5)+5=28+5
3x=33
3x/3=33/3
x=11
For your first question, equate each element to it's counterpart. The equation of the first element is:
$\displaystyle 2\frac{1}{2}-w=\frac{1}{2}+w$
Do this for each element and it's counterpart, and solve for the variable.
For your second question, the problem lies between the 2nd and 3rd steps.
$\displaystyle 3(x-5)+5$ expanded is $\displaystyle 3x-10$. This would mean that $\displaystyle 3(x-5)+5=3x-10=28+5$. The error comes from incorrect application of BODMAS.
The first matrix is equivalent to the second. This means that whatever is in the top left corner of the matrix on the left, is equal to whatever is in the top left corner of the matrix on the right. The same thing goes for each other corner. Equate the two whatevers (known as elements) that correspond to each other i.e, top left = top left, bottom right = bottom right, etc.
Then just use algebra to solve for the variable.