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Math Help - easy log problem, did i get it right?

  1. #1
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    easy log problem, did i get it right?

    problem #1 log_{4} 24 - log_{4} 6

    problem #2 <br />
10log24 - log4

    im doing these two different ways, i kept getting two different answers, can someone please do these the right way so i can understand the procedure, thank you.

    PS: when i type problem 1 in my cal i get the answer 1. but when i do it on paper i get the answer 4, and 1 & 4 are both an answer selection so i dont know which one it is. also, the directions says not to use a calculator though.

    the directions say:
    use the properties of logarithms to find the exact value of the expression. do not use a calculator.
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    How about posting both your attempts..it will be more helpful.. we would be abe to tell you the place you went wrong ..
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  3. #3
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    Quote Originally Posted by ADARSH View Post
    How about posting both your attempts..it will be more helpful.. we would be abe to tell you the place you went wrong ..
    in the first problem i crossed out the log_{4} because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

    and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well
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  4. #4
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    Quote Originally Posted by murkr View Post
    in the first problem i crossed out the log_{4} because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

    and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well
    The basics are very important in these problems

    \ln a - \ln b = \ln (a\div b)

    \log_424- \log_46 = \log_4\frac{24}{6}=\dots

    Also recall

    \log_aa = 1
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  5. #5
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    Quote Originally Posted by murkr View Post
    in the first problem i crossed out the log_{4} because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

    and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well
    log(a) - log(b) in not equal to (a-b).
    Go through the laws of multiplication and division in logarithm.
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  6. #6
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    Quote Originally Posted by pickslides View Post
    The basics are very important in these problems

    \ln a - \ln b = \ln (a\div b)

    \log_424- \log_46 = \log_4\frac{24}{6}=\dots

    Also recall

    \log_aa = 1
    i can do it on my calulator, i do log(24) / log(4) = 2.29
    and log(6) / log(4) = 1.29

    i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again
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  7. #7
    Super Member bigwave's Avatar
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    use the rule mentioned

    Quote Originally Posted by murkr View Post
    i can do it on my calulator, i do log(24) / log(4) = 2.29
    and log(6) / log(4) = 1.29

    i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again
    your calculator asumes a log base of 10 so use the rule mentioned
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  8. #8
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    Quote Originally Posted by bigwave View Post
    your calculator asumes a log base of 10 so use the rule mentioned

    im just not getting it im sorry..
    when you solve the answer yourself without a cal what do you get?
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  9. #9
    Super Member bigwave's Avatar
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    \log_424- \log_46 = \log_4\left(\frac{24}{6}\right)=\log_4{4}=1
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  10. #10
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    Quote Originally Posted by bigwave View Post
    \log_424- \log_46 = \log_4\left(\frac{24}{6}\right)=\log_4{4}=1
    yeah thats the answer i got from doing it on my cal, for some reason i thought doing it on paper would give me a different answer.

    how do i put #3 in a calculator? with #2 i just type in log(24)/log(4) / log(6)/log(4) that equaled 1 for the answer.

    but i dont know how to type in #3 can you help me with that? last qustion i promise
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  11. #11
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by murkr View Post
    problem #1 log_{4} 24 - log_{4} 6

    problem #2 <br />
10log24 - log4

    im doing these two different ways, i kept getting two different answers, can someone please do these the right way so i can understand the procedure, thank you.

    PS: when i type problem 1 in my cal i get the answer 1. but when i do it on paper i get the answer 4, and 1 & 4 are both an answer selection so i dont know which one it is. also,the directions says not to use a calculator though.

    the directions say:
    use the properties of logarithms to find the exact value of the expression. do not use a calculator.

    Quote Originally Posted by murkr View Post
    i can do it on my calulator, i do log(24) / log(4) = 2.29
    and log(6) / log(4) = 1.29

    i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again
    Quote Originally Posted by murkr View Post
    im just not getting it im sorry..
    when you solve the answer yourself without a cal what do you get?
    Quote Originally Posted by murkr View Post
    yeah thats the answer i got from doing it on my cal, for some reason i thought doing it on paper would give me a different answer.

    how do i put #3 in a calculator
    ? with #2 i just type in log(24)/log(4) / log(6)/log(4) that equaled 1 for the answer.

    but i dont know how to type in #3 can you help me with that? last qustion i promise

    Your directions say: Don't use a calculator, so first of all
    Send your calculator to Antarctica.

    You should first of all solve your questions in a paper Here is Logarithm Tutorial.


    Read the link given below(not completely but to your required level) and even then tell us if still need help

    Logarithm - Wikipedia, the free encyclopedia
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