easy log problem, did i get it right?

**murkr** · April 20th 2010, 12:44 AM

problem #1 $log_{4} 24 - log_{4} 6$

problem #2 $<br /> 10log24 - log4$

im doing these two different ways, i kept getting two different answers, can someone please do these the right way so i can understand the procedure, thank you.

PS: when i type problem 1 in my cal i get the answer 1. but when i do it on paper i get the answer 4, and 1 & 4 are both an answer selection so i dont know which one it is. also, the directions says not to use a calculator though.

the directions say:
use the properties of logarithms to find the exact value of the expression. do not use a calculator.

**ADARSH** · April 20th 2010, 12:51 AM

How about posting both your attempts..it will be more helpful.. we would be abe to tell you the place you went wrong ..

**murkr** · April 20th 2010, 05:27 PM

Originally Posted by ADARSH

How about posting both your attempts..it will be more helpful.. we would be abe to tell you the place you went wrong ..

in the first problem i crossed out the $log_{4}$ because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well

**pickslides** · April 20th 2010, 05:34 PM

Originally Posted by murkr

in the first problem i crossed out the $log_{4}$ because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well

The basics are very important in these problems

$\ln a - \ln b = \ln (a\div b)$

$\log_424- \log_46 = \log_4\frac{24}{6}=\dots$

Also recall

$\log_aa = 1$

**sa-ri-ga-ma** · April 20th 2010, 05:35 PM

Originally Posted by murkr

in the first problem i crossed out the $log_{4}$ because they both had the same base which was 4. then i was left with 26 - 4 but i dont know what to do from there.

and then i couldnt do the second problem at all. sorry my attempts are not that good, i dont know the basics to well

log(a) - log(b) in not equal to (a-b).
Go through the laws of multiplication and division in logarithm.

**murkr** · April 20th 2010, 09:13 PM

Originally Posted by pickslides

The basics are very important in these problems

$\ln a - \ln b = \ln (a\div b)$

$\log_424- \log_46 = \log_4\frac{24}{6}=\dots$

Also recall

$\log_aa = 1$

i can do it on my calulator, i do log(24) / log(4) = 2.29
and log(6) / log(4) = 1.29

i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again

**bigwave** · April 20th 2010, 09:24 PM

Originally Posted by murkr

i can do it on my calulator, i do log(24) / log(4) = 2.29
and log(6) / log(4) = 1.29

i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again

your calculator asumes a log base of 10 so use the rule mentioned

**murkr** · April 20th 2010, 09:39 PM

Originally Posted by bigwave

your calculator asumes a log base of 10 so use the rule mentioned

im just not getting it im sorry..
when you solve the answer yourself without a cal what do you get?

**bigwave** · April 20th 2010, 09:56 PM

$\log_424- \log_46 = \log_4\left(\frac{24}{6}\right)=\log_4{4}=1$

**murkr** · April 20th 2010, 10:20 PM

Originally Posted by bigwave

$\log_424- \log_46 = \log_4\left(\frac{24}{6}\right)=\log_4{4}=1$

yeah thats the answer i got from doing it on my cal, for some reason i thought doing it on paper would give me a different answer.

how do i put #3 in a calculator? with #2 i just type in log(24)/log(4) / log(6)/log(4) that equaled 1 for the answer.

but i dont know how to type in #3 can you help me with that? last qustion i promise

**ADARSH** · April 21st 2010, 02:27 AM

Originally Posted by murkr

problem #1 $log_{4} 24 - log_{4} 6$

problem #2 $<br /> 10log24 - log4$

im doing these two different ways, i kept getting two different answers, can someone please do these the right way so i can understand the procedure, thank you.

PS: when i type problem 1 in my cal i get the answer 1. but when i do it on paper i get the answer 4, and 1 & 4 are both an answer selection so i dont know which one it is. also,the directions says not to use a calculator though.

the directions say:
use the properties of logarithms to find the exact value of the expression. do not use a calculator.

Originally Posted by murkr

i can do it on my calulator, i do log(24) / log(4) = 2.29
and log(6) / log(4) = 1.29

i get the answer 1 which is answer A but i dont believe that this is the right answer because in the instructions it says dont use a calculator. can you please do the problem in steps, i find it easier for me to understand it better if i see someone do it. thanks again

Originally Posted by murkr

im just not getting it im sorry..
when you solve the answer yourself without a cal what do you get?

Originally Posted by murkr

yeah thats the answer i got from doing it on my cal, for some reason i thought doing it on paper would give me a different answer.

how do i put #3 in a calculator? with #2 i just type in log(24)/log(4) / log(6)/log(4) that equaled 1 for the answer.

but i dont know how to type in #3 can you help me with that? last qustion i promise

Your directions say: Don't use a calculator, so first of all
Send your calculator to Antarctica.

You should first of all solve your questions in a paper Here is Logarithm Tutorial.

Read the link given below(not completely but to your required level) and even then tell us if still need help

Logarithm - Wikipedia, the free encyclopedia

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