Simple Log problem

**cantstop01** · April 19th 2010, 01:19 AM

Solve algebraically using logs.

$2^x = 5^x+1$

So far I've got $x log 2 = (x+1) log 5$

I think I'm going wrong on the next step. Am I to start isolating X by dividing log 2 by log 5 or is there something I'm missing?

**mathaddict** · April 19th 2010, 02:09 AM

Originally Posted by cantstop01

Solve algebraically using logs.

$2^x = 5^x+1$

So far I've got $x log 2 = (x+1) log 5$

you only do this when the question is $2^x=5^{x+1}$

I think I'm going wrong on the next step. Am I to start isolating X by dividing log 2 by log 5 or is there something I'm missing?

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