What I'm doing (More than likely wrong)
Last edited by desiderius1; Apr 18th 2010 at 10:04 PM.
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According to the answer, the given problem is wrong.
The equation should be equated to 10 rather than 7.
Originally Posted by desiderius1
Answer: This answer is wrong, assuming that you have managed to write down the correct equation that you were asked to solve.
What I'm doing (More than likely wrong) The above equation is very different from the one that you were given. That last step is not valid. More generally, you have that in general .
Sorry, there are two identical problems, one equating to 10 and the other 7, I misread while typing.
The problem is:
Originally Posted by desiderius1 Sorry, there are two identical problems, one equating to 10 and the other 7, I misread while typing.
The problem is: The easy way to solve this equation would be to recognize that the left side really is , and that the solution is simply .
Or else you can first multiply the equation by to get a quadratic equation for :
Thus, we get
But only the case is possible, thus we have
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