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Math Help - Functions

  1. #1
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    Functions

    a. …evaluate and simplify h(0)

    h(x) =

    -15-3x
    ______
    12-6x

    b. …what is the domain of h ? (Be sure to use set notation since domains are sets!)
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by mjfaris View Post
    a. …evaluate and simplify h(0)

    h(x) =

    -15-3x
    ______
    12-6x

    b. …what is the domain of h ? (Be sure to use set notation since domains are sets!)

    h(0)=\frac{-15-3(0)}{12-6(0)}= \frac{-15}{12} = \frac{-5}{4}

    b) the deminator should not equal 0 so

    12-6x = 0 \Rightarrow x=2

    so x all real numbers except 0 as an interval

    (-\infty, 0)\cup (0,\infty)
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  3. #3
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    Quote Originally Posted by Amer View Post
    h(0)=\frac{-15-3(0)}{12-6(0)}= \frac{-15}{12} = \frac{-5}{4}

    b) the deminator should not equal 0 so

    12-6x = 0 \Rightarrow x=2

    so x all real numbers except 0 as an interval

    (-\infty, 0)\cup (0,\infty)
    You mean, surely,
    "so x all real numbers except 2. As an interval

    (-\infty, 2)\cup (2, \infty)
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