Factor an expression containing rational exponents

Factor the expression. Express your answer so that only positive exponents occur.

$\displaystyle

4(6x+3)^{(1/2)}(5x+1)^{(11/7)} + 3(6x+3)^{(3/2)}(5x+1)^{(4/7)} \qquad x>= -\frac{1}{2}

$

The answer:

$\displaystyle

(6x+3)^{(1/2)}(5x+1)^{(4/7)}(38x+13)

$

so far I've done:

$\displaystyle

(24x+12)^{(1/2)}(5x+1)^{(11/7)}+(18x+9)^{(3/2)}(5x+1)^{(4/7)}

$

$\displaystyle

(6x+3)^{(1/2)}(5x+1)^{(4/7)}(4x+4)(5x+1)^{(7/7)}(3x+3)

$

Is that right so far and if so, what do I do next?

Thanks.