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Math Help - Logarithms 2

  1. #1
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    Logarithms 2

    • Can someone show me step by step how to work this out, as I am not good at logs (and I have read through notes). I have 20 similar questions, so it would be a massive help if someone can walk me through, step by step please

    Without using a calculator, solve the following equation for x:

    log (x) = 4 log (2) -2 log (x)

    Thanks
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  2. #2
    Super Member craig's Avatar
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    Post you working so far.

    We can then go through from where you are stuck and take it from there.
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  3. #3
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    I'm not sure if I am on the right track, so I don't have much for this one. I have:

    log (x) = 4 log (2) - 2 log (x)

    log x (x) - 4 x log (2) + 2 log (x)

    I don't know if I'm on the right track, and if I am, I don't know where to go from here.
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  4. #4
    Super Member craig's Avatar
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    Quote Originally Posted by AJShaw View Post
    • Can someone show me step by step how to work this out, as I am not good at logs (and I have read through notes). I have 20 similar questions, so it would be a massive help if someone can walk me through, step by step please

    Without using a calculator, solve the following equation for x:

    log (x) = 4 log (2) -2 log (x)

    Thanks
    Just treat this as a basic algebra question first.

    log (x) = 4 log (2) -2 log (x)

    log (x) + 2 log (x) = 4 log (2)

    3 log (x) = 4 log (2) .

    Remember that \alpha log(\beta) = log(\beta^{\alpha}).

    Now apply the above rule to your question, what do you get?
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