Hello, I'm stumped on this question and need some help.

$\displaystyle \sqrt{5x+7}\frac{1}{2\sqrt{x-6}} + \sqrt{x-6}\frac{1}{3\sqrt{5x+7}} \qquad x > 6$

so far i've done:

$\displaystyle \frac{\sqrt{5x+7}}{2\sqrt{x-6}} + \frac{\sqrt{x-6}}{3\sqrt{5x+7}}$?

Is this correct and if so, what do I do next?

Thanks!