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Math Help - exponents

  1. #1
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    exponents

    Can someone please explain how to simplify these, thanks so much.

    (2b^4)^-1

    (x^2y^-1)^-1

    x^2/2x^3
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  2. #2
    Senior Member ecMathGeek's Avatar
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    Quote Originally Posted by Natalie View Post
    Can someone please explain how to simplify these, thanks so much.

    (2b^4)^-1

    (x^2y^-1)^-1

    x^2/2x^3
    When you have a term raised to a negative exponent, you take the reciprical of the term.

    (2b^4)^-1 = 1/(2b^4)

    (x^2y^-1)^-1 = 1/(x^2y^-1) = y/x^2 <-- notice that the y had a negative exponent and so could be brought back up the numerator

    x^2/(2x^3) <-- in this case, we need to subtract the exponents since the "x"s are the same base. We get
    1/2*x^(2 - 3) = 1/2*x^-1 = 1/(2x)

    If that's not clear, say so and I'll try to explain it better.
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  3. #3
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    Hello, Natalie!


    1) .(2b^4)^-1
    (2b^4)^-1 .= .(2^-1)(b^4)^-1 .= .(2^-1)(b^-4)

    . . . . . . . . 1
    Answer: .-------
    . . . . . . .2b^
    4


    2) .(x^2y^-1)^-1
    (x^2y^-1)^-1 .= .(x^2)^-1(y^-1)^-1 .= .(x^-2)(y)

    . . . . . . . y
    Answer: .---
    . . . . . . .x



    3) .x/2x
    . . . . . . . . x . . . .1
    We have: .---- .= .---
    . . . . . . . .2x . . .2x

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