I'm having diffulculty solving this indices question.. Can anyone show me how its done.

3 (2^n+1) + 5 (2^n)

---------------------------

7 (2^n) - 3 (2^n-1)

Results 1 to 12 of 12

- Apr 14th 2010, 07:38 PM #1

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 07:39 PM #2

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 07:43 PM #3

- Joined
- Jan 2008
- Posts
- 588
- Thanks
- 87

- Apr 14th 2010, 07:43 PM #4

- Joined
- Dec 2009
- From
- 1111
- Posts
- 872
- Thanks
- 3

- Apr 14th 2010, 07:50 PM #5

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 07:58 PM #6

- Joined
- Dec 2009
- From
- 1111
- Posts
- 872
- Thanks
- 3

- Apr 14th 2010, 08:02 PM #7

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 08:13 PM #8

- Joined
- Dec 2009
- From
- 1111
- Posts
- 872
- Thanks
- 3

- Apr 14th 2010, 08:19 PM #9

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 08:29 PM #10

- Joined
- Dec 2009
- From
- 1111
- Posts
- 872
- Thanks
- 3

- Apr 14th 2010, 08:49 PM #11

- Joined
- Jun 2008
- Posts
- 40

- Apr 14th 2010, 09:01 PM #12

- Joined
- Dec 2009
- From
- 1111
- Posts
- 872
- Thanks
- 3