rationalize the denominator $\displaystyle \frac{\sqrt3 - \sqrt 2}{\sqrt 3 + \sqrt 2}$

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- Apr 14th 2010, 05:08 PMeuclid2rationalize denominator
rationalize the denominator $\displaystyle \frac{\sqrt3 - \sqrt 2}{\sqrt 3 + \sqrt 2}$

- Apr 14th 2010, 05:10 PMharish21
- Apr 14th 2010, 05:11 PMeuclid2
- Apr 14th 2010, 05:14 PMharish21
$\displaystyle \frac{\sqrt3 - \sqrt 2}{\sqrt 3 + \sqrt 2}$

$\displaystyle = \frac{\sqrt3 - \sqrt 2}{\sqrt 3 + \sqrt 2} \times \frac{\sqrt3 - \sqrt 2}{\sqrt 3 - \sqrt 2}$

$\displaystyle = \frac{(\sqrt3 - \sqrt2)^2}{(\sqrt3)^2 -(\sqrt2)^2} $

$\displaystyle = \frac{(\sqrt3 - \sqrt2)^2}{3-2}$

Can you finish it now? - Apr 14th 2010, 05:17 PMeuclid2
- Apr 14th 2010, 05:19 PMharish21