Hello, rj2001!

9b² + 24b + 16

. . I got: .(3b + 4)(3b + 4), right? . Right!

But then how do you do this?

I guess factor by grouping . . . . Yes!

. . 4x^6 + 4x^5 - 8x^4 + 8x^3Firsttake out the common factor: .4x³(x³ + x² - 2x + 2)

Factor by grouping: .4x³[x²(x + 1) - 2(x + 1)]

Take out the common factor: .4x³(x + 1)(x² - 2)

(x² + x + 6)(x - 6)

What were the instructions?

It's already factored; it can't be factored any further.

Are they asking us tomultiply?

If so, you'd better review Multiplication of Polynomials.