Results 1 to 8 of 8

Math Help - Solve

  1. #1
    Newbie
    Joined
    Apr 2010
    Posts
    12

    Solve

    I cant seem to find a way to actually find any solutions to this....any suggestions?

    3/(x^2+x)-1/(x+5)=0
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor harish21's Avatar
    Joined
    Feb 2010
    From
    Dirty South
    Posts
    1,036
    Thanks
    10
    Quote Originally Posted by EliteCore View Post
    I cant seem to find a way to actually solve this....any suggestions?

    3/(x^2+x)-1/(x+5)=0
    Where are you stuck at? its easy.

    \frac{a}{b} - \frac{c}{d} = \frac{(a\times d) - (b \times c)}{b \times d}

    follow the above process.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Apr 2010
    Posts
    12
    Quote Originally Posted by harish21 View Post
    Where are you stuck at? its easy.

    \frac{a}{b} - \frac{c}{d} = \frac{(a\times d) - (b \times c)}{b \times d}

    follow the above process.
    Then I get this:

    (3(x+5)-x(x+1))/((x^2+x)(x+5))

    can I go any further?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor harish21's Avatar
    Joined
    Feb 2010
    From
    Dirty South
    Posts
    1,036
    Thanks
    10
    Quote Originally Posted by EliteCore View Post
    Then I get this:

    (3(x+5)-x(x+1))/((x^2+x)(x+5))

    can I go any further?
    never mind.. i misread your answer.. Your expression is correct

    now expand the numerator by multiplying the terms
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    29
    Now expand the numerator and group like terms.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    Joined
    Dec 2007
    From
    Ottawa, Canada
    Posts
    3,161
    Thanks
    70
    If numerator / denominator = 0, then numerator = 0
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    Apr 2010
    Posts
    12
    is (-(x-5))/(x(x+2))

    the answer?
    Follow Math Help Forum on Facebook and Google+

  8. #8
    MHF Contributor harish21's Avatar
    Joined
    Feb 2010
    From
    Dirty South
    Posts
    1,036
    Thanks
    10
    Quote Originally Posted by EliteCore View Post
    is (-(x-5))/(x(x+2))

    the answer?
    NO.

     \frac{3(x+5)-x(x+1)}{(x^2+x)(x+5)} is what you had gotten.

    according to your question, this term = 0, so you have,

     \frac{3(x+5)-x(x+1)}{(x^2+x)(x+5)} = 0

    Look at what Wilmer has said in the post above. That gives you:

    3(x+5)-x(x+1) = 0

    3x+15-x^2-x=0

    2x+15-x^2=0

    x^2-2x-15=0

    Solve this quadratic equation for the value of x!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. need to solve summation equation to solve sum(x2)
    Posted in the Statistics Forum
    Replies: 2
    Last Post: July 16th 2010, 11:29 PM
  2. Replies: 1
    Last Post: June 9th 2009, 11:37 PM
  3. how do i solve this?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 2nd 2008, 03:58 PM
  4. how to solve ..
    Posted in the Advanced Algebra Forum
    Replies: 0
    Last Post: August 2nd 2008, 09:17 AM
  5. please help me solve this
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 1st 2008, 10:50 PM

Search Tags


/mathhelpforum @mathhelpforum