# Thread: Simple problem... rearranging fractional exponent expression

1. ## Simple problem... rearranging fractional exponent expression

This should be simple. Show that

$\displaystyle (\frac{2meE}{h^2})^{1/3}x = (\frac{2m}{h^2 e^2 E^2})^{1/3}eEx$

For some odd reason, I can't seem to get it. Any ideas?

2. Originally Posted by Ares_D1
This should be simple. Show that

$\displaystyle (\frac{2meE}{h^2})^{1/3}x = (\frac{2m}{h^2 e^2 E^2})^{1/3}eEx$

For some odd reason, I can't seem to get it. Any ideas?
$\displaystyle \bigg{(}\frac{2meE}{h^2}\bigg{)}^{1/3}x = \bigg{(}\frac{2meE}{h^2} \cdot \frac{e^2}{e^2} \cdot \frac{E^2}{E^2}\bigg{)}^{1/3}$

$\displaystyle = \bigg{(}\frac{2me^3E^3}{e^2 E^2 h^2}\bigg{)}^{1/3}x = \bigg{(}\frac{2m}{h^2e^2 E^2}\bigg{)}^{1/3}eEx$