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**fizzle45** Hi, I am probably an idiot for missing this but im sick of staring at this problem i thought i would come here to be enlightened. anyways

phase 1

assuming n,m > 0 and real numbers and m > n

$\displaystyle \frac{1}{2^n}\left(1+\frac{1}{2}+...+\frac{1}{2^{m-n-1}}\right)$

phase 2

$\displaystyle \frac{1}{2^n}\cdot\frac{\left(1-(\frac{1}{2})^{m-n-1+1}\right)}{1-\frac{1}{2}}$

there are all equal statements im told, but I have no clue the 'trick' to widdle this down from phase 1 to phase 2. thanks in advance