Hey guys I am new to this website and wanted some help. I would like to see the steps if possible. Thank you! Solve for t or x. Round off 3 significant decimals ln(t/t-2)=1 5^(t+1)=6^t ln9x=1 2=e^(.6t) 1/5=e^(4x) 9ln x = 15 ln 3 + ln x= 1.4
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Originally Posted by Jackie10 Hey guys I am new to this website and wanted some help. I would like to see the steps if possible. Thank you! Solve for t or x. Round off 3 significant decimals ln(t/t-2)=1 5^(t+1)=6^t ln9x=1 2=e^(.6t) 1/5=e^(4x) 9ln x = 15 ln 3 + ln x= 1.4 I'll take you through them one at a time if you like, but first show me how you would start Q1.
Originally Posted by Jackie10 Hey guys I am new to this website and wanted some help. I would like to see the steps if possible. Thank you! Solve for t or x. Round off 3 significant decimals ln(t/t-2)=1 5^(t+1)=6^t ln9x=1 2=e^(.6t) 1/5=e^(4x) 9ln x = 15 ln 3 + ln x= 1.4 .
Originally Posted by Jackie10 Hey guys I am new to this website and wanted some help. I would like to see the steps if possible. <<<<< we also Thank you! Solve for t or x. Round off 3 significant decimals ... 5^(t+1)=6^t ... 1. I assume that you are familiar with the basic laws of powers and logarithms. 2.
Originally Posted by Jackie10 Hey guys I am new to this website and wanted some help. I would like to see the steps if possible. Thank you! Solve for t or x. Round off 3 significant decimals ln(t/t-2)=1 5^(t+1)=6^t ln9x=1 2=e^(.6t) 1/5=e^(4x) 9ln x = 15 ln 3 + ln x= 1.4
So for 2=e^.6t do i take ln of both sides ln2=lne^.6t then lne=1 ln2=.6931 .6931=.6t to get t i divide by .6 to both sides then i get .6931/.6 t=1.155
Originally Posted by Jackie10 So for 2=e^.6t do i take ln of both sides ln2=lne^.6t then lne=1 ln2=.6931 .6931=.6t to get t i divide by .6 to both sides then i get .6931/.6 t=1.155 Correct!!
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