Hi, and thanks for your reply,

First up the code option is rather exciting - gonna have a go at that is a sec...

With the first problem am I rite in saying you have divided by 3 because it's the greatest common factor?

Now... I'm going to try coding my answer to the second problem:

Regarding $\displaystyle \frac{(4x^{3}y)^2}{x^5} = \frac{4x^{3}y \times 4x^{3}y}{x^5}

$

So effectively we are performing $\displaystyle \frac{4x^{3}y}{x^5}$ twice to acount for the fact that the top part is raised to the power of 2?

So $\displaystyle \frac{4x^{3}y}{x^5} = \frac{4y}{x^2}$

Meaning $\displaystyle \frac{4x^{3}y \times 4x^{3}y}{x^5} = \frac{16y^2}{x^4} $ ??

Thanks in advance for your help

- James