If x=2 and xy does not =0, what is the value of
x^4*y^4 - (xy)^2 / x^3 * y^2
My answer is 3y^2 / 2y^2...but not sure if that is the answer or should I just say 3/2?
I assume this problem is
(x^4*y^4 - x^2*y^2)/(x^3*y^2)
I'm not sure where you got 3y^2 / 2y^2, but I don't see that you can get that from this.
If we break up the fraction, we get
(x^4*y^4)/(x^3*y^2) - (x^2*y^2)/(x^3*y^2) = x*y^2 - 1/x
Maybe I'm misunderstanding the problem.
yes, if that is the answer, you should say 3/2, but how did you get that answer? am i misinterpreting the problem? please type clearly, use brackets to show what is being divided by what.
i think the problem is:
[x^4*y^4 - (xy)^2]/(x^3*y^2)
= [x^4*y^4 - x^2*y^2]/(x^3*y^2)
= [(x^2*y^2)(x^2*y^2 - 1)]/(x^3*y^2)
= (x^2*y^2 - 1)/(x)
= (4y^2 - 1)/2
i plugged in x = 2 in the final step. i didn't split the fraction up as ecMathGeek did
Okay...let me try to re-write again. There was a slight typo on the first y^2.
If x=2 and xy does not =0, what is the value of
(x^4)*(y^2) - (xy)^2 / (x^3) * (y^2) =
I plugged in x to get the following
16*(y^2) - 4*(y^2) / 8*(y^2)
then
12*(y^2) / 8*(y^2)
then reduce
3(y^2) / 2(y^2)
Is that still wrong?
[(x^4)*(y^2) - (xy)^2] / [(x^3) * (y^2)] - indeed was what I meant.
I am so sorry for the confusion...I should have put the outside set of parentheses on the numerator problem.
So...bearing that in mind...my answer is correct?